일반 화학 5판 解法(해법) 자유
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작성일 19-06-19 22:06본문
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일반 화학 자유 5판
일반 화학 자유 5판챕터2 , 일반 화학 5판 솔루션 자유화학솔루션 , 일반 화학 자유 chapter2
일반 화학 5판 解法(해법) 자유
chapter 2
atoms, molecules, and ions
2.7 First, convert 1 cm to picometers.
2.8 Note that you are given information to set up the unit factor relating meters and miles.
2.11 For iron, the atomic number Z is 26. Therefore the mass number A is:
A ? 26 ? 28 ? 54
2.12 Strategy: The 239 in Pu-239 is the mass number. The mass number (A) is the total number of neutrons and protons present in the nucleus of an atom of an element. You can look up the atomic number (number of protons) on the periodic table.
Solution:
mass number ? number of protons ? number of neutrons
number of neutrons ? mass number ( number of protons ? 239 ( 94 ? 145
2.13 Isotope
No. Protons 2 2 12 12 22 35 78
No. Neutrons 1 2 12 13 26 44 117
2.14 Isotope
No. Protons 7 16 29 38 56 74 80
No. Neutrons 8 17 34 46 74 112 122
No. Electrons 7 16 29 38 56 74 80
2.15 (a) (b)
2.16 The accepted way to denote the atomic nu
일반,화학,자유,chapter2,화학,솔루션
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솔루션/화학
챕터2
순서
다.